Arithmetic pricing model
In this problem, we explore how an arithmetic sequence can model a simple pricing structure. This connects directly to the HSC Sequences topic, where recognising linear growth patterns unlocks quick formula-building and inequality solving. By working through this example, you’ll practise translating a word problem into a sequence formula and then using it to answer both evaluation and budget-limit questions.
Problem Statement
An installer charges $400 for the first window and $100 for each additional window.
- Write the total cost for 1, 2, 3, and 4 windows.
- Find a formula for the total cost for windows.
- Find .
- If the budget is strictly less than $10,000, what is the maximum number of windows?
Hints
Model as an arithmetic sequence with first term and difference .
Solutions
We begin by listing the costs for the first few numbers of windows. The first window costs $400, and every extra window adds $100:
The cost of windows follows an arithmetic progression with first term and common difference . The th term of an arithmetic sequence is , so
This compact formula now lets us answer any number of windows. Substituting gives the total cost directly: So .
Finally, we translate the budget restriction into an inequality. The total cost must be strictly less than $10,000, so
hence the maximum integer number of windows is .
Takeaways
- Recognise that a constant addition ($100 per window) signals an arithmetic sequence; the first term and common difference are all you need.
- Build the explicit formula and then use it for both simple evaluations and inequality constraints.
- When an inequality gives a non-integer bound (like ), always round down to the nearest integer to stay within the strict budget limit.
Further Readings
HSC Sequences, HSC Vectors, HSC Differential Equations, HSC Probability