Arithmetic nth term

#hsc-maths#sequences#basic

Arithmetic sequences are one of the simplest patterns in mathematics, and the ability to jump directly to any term is a foundational skill for HSC Mathematics. In this problem, we practice using the explicit formula for the nnth term to find a30a_{30} given the first term and common difference. Mastering this technique will serve you well when tackling more complex series questions.

Problem Statement

An arithmetic sequence has first term 44 and common difference 55. Find a30a_{30}.


Solutions

To find the 30th term, we apply the formula for the nnth term of an arithmetic sequence, which links the first term, the common difference, and the term number. Since we want the 30th term, we set n=30n=30; the number of steps from the initial term is n1=29n-1=29. Substituting a=4a=4 and d=5d=5 into an=a+(n1)da_n = a + (n-1)d gives:

a30=4+295=149.a_{30}=4+29\cdot 5=149.

Takeaways

  • The nnth term of an arithmetic sequence with first term aa and common difference dd is an=a+(n1)da_n = a + (n-1)d.
  • Direct substitution of the given values yields the answer without needing to list terms step by step.
  • Always check that you multiply the common difference by (n1)(n-1), not by nn.

Further Readings

HSC Last Resorts, HSC Complex Numbers, HSC Collections, HSC Integrals

Written by Vu Hung Nguyen

Mathematics Educator · LinkedIn · About