Infinite geometric interpretation

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Converting recurring decimals to fractions is a classic application of infinite geometric series, a key skill in the HSC Extension 1 Sequences and Series topic. By splitting the decimal into a terminating part and a recurring part, we can use the sum-to-infinity formula for a geometric progression to express the number exactly as a fraction. This problem demonstrates that technique for a decimal with a delayed repeating block.

Problem Statement

Evaluate

0.42=0.422220.4\overline{2}=0.42222\ldots

as a fraction.


Hints

Write as 0.4+0.022220.4+0.02222\ldots and convert the recurring part using a GP.


Solutions

Following the hint, we write 0.420.4\overline{2} as 0.4+0.022220.4 + 0.02222\ldots. The recurring decimal 0.022220.02222\ldots can be seen as the infinite geometric series 0.02+0.002+0.0002+0.02 + 0.002 + 0.0002 + \dots with first term a=0.02a = 0.02 and common ratio r=0.1r = 0.1. Since r=0.1<1|r| = 0.1 < 1, the series converges, and applying the sum-to-infinity formula S=a1rS = \frac{a}{1-r} gives

0.02222=290=145.0.02222\ldots=\frac{2}{90}=\frac{1}{45}.

Now we combine this with the non-repeating part, 0.4=250.4 = \frac{2}{5}, and add the two fractions:

0.42=25+145=1845+145=1945.0.4\overline{2}=\frac{2}{5}+\frac{1}{45}=\frac{18}{45}+\frac{1}{45}=\frac{19}{45}.

Takeaways

  • Isolate the repeating block as a geometric series; its first term aa and common ratio r=10kr = 10^{-k} (where kk is the length of the repeating block) let you apply the sum-to-infinity formula.
  • The sum-to-infinity formula S=a1rS = \frac{a}{1-r} (valid for r<1|r|<1) converts the recurring part directly to a fraction.
  • Adding the terminating decimal part, also expressed as a fraction, gives the final rational representation.

Further Readings

HSC Trigonometry, HSC Last Resorts, HSC Polys Ext 1, HSC Complex Numbers

Written by Vu Hung Nguyen

Mathematics Educator · LinkedIn · About