Quick Chebyshev value

#hsc-maths#sequences#basic

Second-kind Chebyshev polynomials often surface in HSC Extension 1 and 2 work when exploring trigonometric identities or series expansions. This short exercise gives you a chance to practise direct algebraic substitution with fractions—an essential skill that sets you up for success when the algebra gets heavier. This type of question often appears in the Extension 1 topic Further Trigonometry, where Chebyshev polynomials are used to express cosnθ\cos n\theta as a polynomial in cosθ\cos\theta.

Problem Statement

For the second-kind Chebyshev polynomial

U2(x)=4x21,U_2(x)=4x^2-1,

find U2(12)U_2\left(\frac12\right).


Hints

Substitute x=12x=\frac12 carefully.


Solutions

We substitute x=12x = \frac12 directly into the expression. Since (12)2=14\left(\frac12\right)^2 = \frac14, the 4x24x^2 term becomes 4×14=14 \times \frac14 = 1, cancelling neatly with the 1-1 to give zero.

U2(12)=4(14)1=11=0.U_2\left(\frac12\right)=4\left(\frac14\right)-1=1-1=0.

Takeaways

  • For a given Chebyshev polynomial, direct substitution is often enough.
  • Square fractions before multiplying by the coefficient.

Further Readings

HSC Trigonometry, HSC Last Resorts, HSC Mechanics, HSC Vectors

Written by Vu Hung Nguyen

Mathematics Educator · LinkedIn · About